The 1940 United States presidential election in Arizona took place on Tuesday, November 5, 1940, as part of the nationwide presidential election. Arizona voters selected three electors to the Electoral College, which ultimately voted for president and vice president.
Candidates
| Party | Nominee | Running mate | Home state |
|---|---|---|---|
| Democratic | Franklin D. Roosevelt (incumbent) | Henry A. Wallace | New York |
| Republican | Wendell Willkie | Charles L. McNary | New York |
Results
| Candidate | Popular vote | Percentage |
|---|---|---|
| Franklin D. Roosevelt (Democratic) | 88,481 | 63.30 % |
| Wendell Willkie (Republican) | 50,901 | 36.47 % |
| Others | 657 | 0.23 % |
| Total | 140,039 | 100 % |
- Roosevelt carried all three of Arizona’s electoral votes.
Context
- The election occurred during the early years of World II, though the United States had not yet entered the conflict.
- Roosevelt’s victory in Arizona reflected the state’s Democratic leaning at the time, continuing a pattern of support for the New Deal coalition.
- Voter turnout in Arizona was consistent with national trends, with a slight increase compared to the 1936 election.
Aftermath
Franklin D. Roosevelt was inaugurated for his third term as President of the United States on January 20, 1941. Arizona’s support contributed to his decisive national victory, in which he won 38 of the 48 states and secured 449 electoral votes.
